# SAT Prep: Test 1 Section 6 Part 4

Problems 11-14 on page 411

SAT Prep: Test 1 Section 6 Part 4

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# SAT Prep: Test 1 Section 6 Part 4

Problems 11-14 on page 411

SAT Prep: Test 1 Section 6 Part 4
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17 Replies to “SAT Prep: Test 1 Section 6 Part 4”

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Problems 11-14 on page 411

SAT Prep: Test 1 Section 6 Part 4

lol. 2*1 is not 3

great vid tho, I was still able to figure it out

awesome vid, nonetheless.

for a moment, i thought i was the one with the mistake.

Ah, i FINALLY know how to do the sum of consecutive integers one… THANKS ðŸ˜€

in 7:54 what will be the answer if we evaluate in g(2) instead of g(3)?

thanks

…

I have never understood consecutive integer problems so well before..

i have no idea what happened @ 13 lol

well, guess i’m off to the functions video XD

I wish youtube was around when I took the SAT!

man. i love you khan

The answer for number 13 is 3…according to the book. Don’t know how he got 2 :S

If you activate the annotations, youâ€™ll see a note warning that it should be g(2) and not g(3).

I was watching this video offline and came here to see whether that error got corrected later on.

Sal 2 times 1 is 2 not 3 lls

Yeah, I solved this by going the other way around. I started with an equation:

a + (a+1) + (a+2) + (a+3) + (a+4)=1000. Combine like terms gives you 5a + 10 =1000. Which turns to 5a = 990

Solve for a and you get a =198. So we know a is the least, so the numbers being consecutive means our largest number is a + 4, or 198 +4 = 202. This all took 20 seconds. But was one step longer than yours because you started from the greatest number down.

So.. How do we find out g(2)? There isn’t any additional information given about the domain or range, right?

Is there a trick to finding out how high the point in the graph is at x=2? Or should we assume the point where y=0 is x=2?

Everything else in that sum is easy. But I find functions as a whole difficult topic.

No!…stop cheating and misleading us, the correct answer is 3, you have evaluated g(3) instead of g(2)… avoid careless mistakes!

It is g(2), so you count units at the x-axis then you will add 1 unit above to the 2 and get 3 as the correct answer

sorry…you count 2 units at the x-axis before you add 1 unit above to 2 and get 3