New SAT – Official Test #1 – Math Section 4 – Q21-30

The New SAT tips tricks and strategies – Practice Test #1 – Math Section 4 – Q21-30 LINK:
New SAT – Official Test #1 – Math Section 4 – Q21-30

31 Replies to “New SAT – Official Test #1 – Math Section 4 – Q21-30”

  1. Wait. at question 26, what i did was, since, Type A trees produced 20% more than type B trees, I took 20% from 144 and subtracted it from 144 to get Type B trees. (Since Type A trees produce 20 more) But why did I get about 115 instead of 120???

  2. Question 26 i believe is wrong …. sorry if i am interfering but i did it several times and it is impossible to get 120 …. could you please recheck

  3. I think for Q29, the answer is D bc (x-3) is x=3, and as we can see from the point you derived from the question, y is -2 when x is 3. the remainder is the same thing as y

  4. 29. p(x) =(x-3)(x+2) so the solved version of x+2 equals -2. So it’s if you divide p(x) by x-3(x=3) you get x+2(x=-2), I believe it’s looking for the solutions plural, instead of x and y.

  5. Hey! Your videos are a big help. I was curious to know that if you get a question wrong do you just cut it out? or do you look beforehand at the questions, or are you just that smart!?

  6. ……It is Easy…..Incredibly Easy i did This At My second year of high school ……..I did a test To enter University This year And i Can only Say that It was world apart from This, in America you need only To have This level To enter college? To think i’m Not Even good At Math But At least Now i know that The Math i did At My third fourth And fifth year of high school is The Math of college in America i’m proud of myself

  7. The explanation for question 29 is with something called the remainder theorem.

    It means that if any polynomial is divided by a binomial with the format (x+a) such as (x+1) or (x-3), then after the division, anything left that could not be fully divided into the polynomial (aka “remainder”) can be found by inputing “-a” (negative a) into the original equation and you’ll get a y-value.

    That y-value is the remainder.

    So in the question, if you divide a polynomial by (x-3), then you take the negative of -3 (which is 3) and input that into an equation, and you get a remainder. The question says that f(3) is -2, so the remainder is -2 by this theorem.

    Sorry my explanation is so long :/

  8. I found how to get to the answer for Q. 29. min 19:26. …p(3)=-2 gives the value of p as -2/3. … when you divide -2/3 by (x-3) you will get -2. which explains option D.

  9. There’s a rule for question 29 it’s of p(3)= a number the root will be x-3 and if p(4)=# the root for it is x-4

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