# Test 3 Section 2 Part 5

Problems 18-20 on starting on page 522

Test 3 Section 2 Part 5

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# Test 3 Section 2 Part 5

Problems 18-20 on starting on page 522

Test 3 Section 2 Part 5
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3 Replies to “Test 3 Section 2 Part 5”

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Problems 18-20 on starting on page 522

Test 3 Section 2 Part 5

is there a faster way of doing number 20?

I don’t think so.

For #20, a faster way of doing it is subtracting 3 from 15 (since you know the answer has a remainder of 3), and finding all the factors of that number. You can do this b/c k will go into the part of the answer that doesn’t have a remainder perfectly (i.e. w/o a remainder). So 15 – 3 = 12, and you would find all the factors of 12, which are 4,3,6, and 2. Except k can’t equal 3 b/c it wouldn’t make sense to have a remainder of 3 if k=3. So k would be true for 3 values instead of 4.